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  <title>众茶通</title>
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      let response = JSON.parse(xmlhttp.responseText)
      console.log("参数response：",response.result.remark);
      document.getElementById('content').innerHTML = response.result.remark
    }
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  let requestUrl = "http://zcgj-api.utea88.com/front/advisement/getById?id=26"
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</script>
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